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(10p^2)/(35.600-(5p^2))=1
We move all terms to the left:
(10p^2)/(35.600-(5p^2))-(1)=0
Domain of the equation: (35.600-5p^2)!=0We multiply all the terms by the denominator
We move all terms containing p to the left, all other terms to the right
-5p^2!=-35.600
p^2!=-35.600/-5
p^2!=√7+0.6/5
p!=2.64575131106
p∈R
10p^2-1*(35.600-5p^2)=0
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